Chemistry Take Home #3

Um - didn't he say it would be posted by 5:00 this afternoon? Does anyone else see it on Blackboard?

I sent him email around 11:30pm last night so I could get started. I sort of hated doing that. I knew he would still expect it done Thursday. I'm afraid I am out of the mood. I keep looking at it & feeling duhhh
Take home was posted between 9:30am & 11am this morning.

Is that seriously a quadratic formula problem on the first one?

God help us all..

HA HA AH HA. I laughed out loud, Kyle. Funniest thing I heard all week.
You know he isn't going to require us to do those things without the formulas.
But now, I'm not laughing any more.

I seriously believe it is.

what did you guys put for the Molar concentration of the NaOH in Lab 9? The bottle said N/10.
Do we use 0.1000 M?

And...it's an impossible quadratic equation to do as well (it's negative under the square root sign).

I really want to just throw it in the trash.


*And yes Lisa, .1000

Did he say that the diprotic had the two different concentrations for the equiv points, and the monoprotic had equal concentrations?

I bet Shauna went to bed already.

I don't have it in my notes. What I do have is that, if it is a diprotic acid, there will only be one concentration for us to report. It seems I recall him saying that if it were 2 different acids, they would give us equal concentrations of both? Can anybody confirm? I'm only at the point where I know I used 20.95 ml at one EqPt, and 27.25 at the second point.

I am hoping this is correct for finding the concentrations - wait. I don't know if I have diprotic. I don't seem to have the proper ratios of NaOH used, so I dont think it's diprotic.
1st Equiv Point ml NaOH x L/1000 ml x 0.5 moles = concentration
2nd Equiv Point ml NaOH x L/1000 ml x 0.05 moles = concentration
Is this right?